Ionic EquilibriumhardNUMERICAL

Two separate solutions of weak monoprotic acids, () and (), are found to be perfectly isohydric. If Ionic Equilibrium Chemistry Question

Question

Two separate solutions of weak monoprotic acids, $HA_1$ ($K_{a1} = 10^{-4}$) and $HA_2$ ($K_{a2} = 10^{-5}$), are found to be perfectly isohydric. If the concentration of $HA_1$ is exactly $0.1 \text{ M}$, calculate the exact required molar concentration ($C_2$) of $HA_2$.

Answer: 1

💡 Solution & Explanation

Isohydric solutions are solutions of electrolytes that have the exact same concentration of a common ion (in this case, $[H^+]$). For weak acids, $[H^+] \approx \sqrt{K_a \cdot C}$. Equating the two yields $\sqrt{K_{a1}C_1} = \sqrt{K_{a2}C_2}$, which squares to the identity $K_{a1}C_1 = K_{a2}C_2$. Substituting the provided values gives $(10^{-4})(0.1) = (10^{-5}) \cdot C_2 \implies 10^{-5} = 10^{-5} \cdot C_2 \implies C_2 = 1.0 \text{ M}$.

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