If the molar solubility of lithium sodium hexafluoroaluminate, , is denoted by '' , its solubility p — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The salt dissociates as: $Li_3Na_3(AlF_6)_2 \rightleftharpoons 3Li^+ + 3Na^+ + 2AlF_6^{3-}$. If the solubility is $s$, then at equilibrium: $[Li^+] = 3s$, $[Na^+] = 3s$, and $[AlF_6^{3-}] = 2s$. The solubility product expression is $K_{sp} = [Li^+]^3 [Na^+]^3 [AlF_6^{3-}]^2$. Substituting the values: $K_{sp} = (3s)^3 \times (3s)^3 \times (2s)^2 = (27s^3) \times (27s^3) \times (4s^2) = 2916s^8$.