What will be the exact solubility of solid () in a aqueous solution of ? — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The $NaCl$ fully dissociates to yield a $[Cl^-]$ of $0.1 \text{ M}$. The dissolution of $AgCl$ is $AgCl \rightleftharpoons Ag^+ + Cl^-$. Let solubility be $s$. Total $[Cl^-] = 0.1 + s \approx 0.1 \text{ M}$ (since $s$ is very small due to common ion effect). $K_{sp} = [Ag^+][Cl^-] \Rightarrow 1.6 \times 10^{-10} = (s)(0.1) \Rightarrow s = 1.6 \times 10^{-9} \text{ M}$.