Ionic EquilibriummediumMCQ SINGLE

When of are added to a litre of a buffer solution, its pH changes from to . What is its exact bufferIonic Equilibrium Chemistry Question

Question

When $0.02 \text{ moles}$ of $NaOH$ are added to a litre of a buffer solution, its pH changes from $5.75$ to $5.80$. What is its exact buffer capacity?

Answer: A

💡 Solution & Explanation

Buffer capacity ($\beta$) is defined as the number of moles of acid or base added per liter of the buffer divided by the change in pH. $\beta = \frac{\Delta n}{\Delta pH} = \frac{0.02}{5.80 - 5.75} = \frac{0.02}{0.05} = 0.4$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry