In the catalytic aromatization of exactly one mole of pure n-hexane into benzene using at 773 K, how many moles of hydrogen gas () are theoretically evolved as a byproduct?

Question

In the catalytic aromatization of exactly one mole of pure n-hexane into benzene using $Cr_2O_3/Al_2O_3$ at 773 K, how many moles of hydrogen gas ($H_2$) are theoretically evolved as a byproduct?

Prashant Kotian · Accepted Answer

Correct answer: 4. The chemical formula for n-hexane is . The chemical formula for benzene is . The aromatization process involves removing hydrogen atoms to create the double bonds of the aromatic ring. The balanced equation is . Therefore, exactly 4 moles of hydrogen gas are evolved.

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