HydrocarbonsmediumNUMERICAL

In the planar hexagonal geometry of benzene, the bond angles are defined by the trigonal planar geomHydrocarbons Chemistry Question

Question

In the planar hexagonal geometry of benzene, the $C-C-C$ bond angles are defined by the trigonal planar geometry of the constituent carbon atoms. What is the value of this angle in degrees?

Answer: 120

💡 Solution & Explanation

Because every carbon atom in benzene utilizes strictly $sp^2$ hybridization and no lone pairs are present on the carbons, the molecular geometry at each center is perfectly trigonal planar, imposing a strict $120^{\circ}$ bond angle. This perfectly matches the internal angle of a regular hexagon, making the ring fully strain-free.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry