An unknown alkene 'A' is subjected to complete reductive ozonolysis ( followed by ) and yields exact — Hydrocarbons Chemistry Question

💡 Solution & Explanation

An aldehyde with a molar mass of 44 g/mol is acetaldehyde/ethanal ($CH_3CHO$: $12 + 1 + 12 + 1 + 16 = 44$). Since reductive ozonolysis produces exactly two moles of $CH_3CHO$ and no other products, the original alkene must be symmetrical and contain two $CH_3-CH=$ groups. Rejoining these fragments at the double bond yields $CH_3-CH=CH-CH_3$, which is But-2-ene.