Consider the molecule hex-1-en-5-yne (). Following standard IUPAC numbering, what are the hybridizat — Hydrocarbons Chemistry Question
Question
Consider the molecule hex-1-en-5-yne ($CH_2=CH-CH_2-CH_2-C\equiv CH$). Following standard IUPAC numbering, what are the hybridization states of the $C_2$ and $C_3$ carbon atoms, respectively?
Answer: D
💡 Solution & Explanation
According to IUPAC nomenclature rules, when numbering a chain with both a double and triple bond at equivalent positions, the double bond gets the lower number. Thus, numbering starts from the alkene side: $C_1H_2=C_2H-C_3H_2-C_4H_2-C_5\equiv C_6H$. $C_2$ is part of the double bond and is $sp^2$ hybridized. $C_3$ has only single bonds and is $sp^3$ hybridized.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes