Consider the molecule hex-1-en-5-yne (). Following standard IUPAC numbering, what are the hybridization states of the and carbon atoms, respectively?

Question

Consider the molecule hex-1-en-5-yne ($CH_2=CH-CH_2-CH_2-C\equiv CH$). Following standard IUPAC numbering, what are the hybridization states of the $C_2$ and $C_3$ carbon atoms, respectively?

Prashant Kotian · Accepted Answer

Correct answer: D. According to IUPAC nomenclature rules, when numbering a chain with both a double and triple bond at equivalent positions, the double bond gets the lower number. Thus, numbering starts from the alkene side: . is part of the double bond and is hybridized. has only single bonds and is hybridized.

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