In the highly stable, aromatic tropylium cation (), how many total -electrons are continuously deloc — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

The tropylium cation ($C_7H_7^+$) is a seven-membered ring with three conjugated double bonds and one carbocation center. Each double bond contributes two $\pi$ -electrons, totaling $3 \times 2 = 6$ delocalized $\pi$ -electrons, satisfying Huckel's ($4n+2$) rule for aromaticity.