Find the total number of sigma () bonds present in the structure of 2-ethyl-3-methylpent-1-ene. — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

The molecular formula for 2-ethyl-3-methylpent-1-ene is $C_8H_{16}$ ($CH_2=C(CH_2CH_3)-CH(CH_3)-CH_2-CH_3$). For an acyclic hydrocarbon, total bonds = (Total Atoms - 1). Total atoms = 8 + 16 = 24. Total bonds = 23. Since there is exactly 1 $\pi$ bond, there are 23 $\sigma$ bonds. Alternatively: 7 C-C $\sigma$ bonds + 16 C-H $\sigma$ bonds = 23.