In the hydrocarbon , what is the state of hybridization of carbons 1, 3, and 5 (numbering from left — GOC and Organic Chemistry Basics Chemistry Question
Question
In the hydrocarbon $HC\equiv C-CH_2-CH=CH-CH_3$, what is the state of hybridization of carbons 1, 3, and 5 (numbering from left to right as per IUPAC rules giving the triple bond the lowest locant)?
Answer: C
💡 Solution & Explanation
Numbering starts from the triple bond: C1 is $sp$ hybridized (triple bond), C3 is $sp^3$ hybridized (all single bonds), and C5 is $sp^2$ hybridized (double bond). Thus, the sequence is $sp, sp^3, sp^2$.
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