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The standard electrode potential () values of , , and are , , and , respectively. The correct decreaElectrochemistry Chemistry Question

Question

The standard electrode potential ($E^\circ$) values of $Al^{3+}/Al$, $Ag^+/Ag$, $K^+/K$ and $Cr^{3+}/Cr$ are $-1.66\text{ V}$, $+0.80\text{ V}$, $-2.93\text{ V}$ and $-0.74\text{ V}$, respectively. The correct decreasing order of the reducing power of these metals is:

Answer: A

💡 Solution & Explanation

The reducing power of a metal increases as its standard reduction potential ($E^\circ$) becomes more negative, indicating a stronger tendency to lose electrons (be oxidized). The order of $E^\circ$ is $K (-2.93\text{ V}) < Al (-1.66\text{ V}) < Cr (-0.74\text{ V}) < Ag (+0.80\text{ V})$. Thus, the decreasing order of reducing power is $K > Al > Cr > Ag$.

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