A neutral atom of Uranium () possesses the atomic number . What is the theoretical maximum oxidation — d and f Block Elements Chemistry Question
Question
A neutral atom of Uranium ($U$) possesses the atomic number $92$. What is the theoretical maximum oxidation state it can stably exhibit in compounds like its hexafluoride ($UF_6$) or the uranyl ion ($UO_2^{2+}$)?
Answer: 6
💡 Solution & Explanation
Uranium ($Z=92$) has a ground state electronic configuration of $[Rn] 5f^3 6d^1 7s^2$. By utilizing all 6 of these valence electrons in bonding, it can reach an absolute maximum oxidation state of $+6$, as prominently seen in compounds like $UF_6$ and the highly stable $UO_2^{2+}$ ion.
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