A neutral atom of Uranium () possesses the atomic number . What is the theoretical maximum oxidation state it can stably exhibit in compounds like its hexafluoride () or the uranyl ion ()?

Question

A neutral atom of Uranium ($U$) possesses the atomic number $92$. What is the theoretical maximum oxidation state it can stably exhibit in compounds like its hexafluoride ($UF_6$) or the uranyl ion ($UO_2^{2+}$)?

Prashant Kotian · Accepted Answer

Correct answer: 6. Uranium () has a ground state electronic configuration of . By utilizing all 6 of these valence electrons in bonding, it can reach an absolute maximum oxidation state of , as prominently seen in compounds like and the highly stable ion.

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