According to Crystal Field Theory, what are the respective values of the crystal field stabilization — Coordination Compounds Chemistry Question

💡 Solution & Explanation

**Octahedral High-Spin $d^6$:** Configuration is $t_{2g}^4 e_g^2$. $\text{CFSE} = [-0.4(4) + 0.6(2)]\Delta_o = [-1.6 + 1.2]\Delta_o = -0.4\Delta_o$. **Tetrahedral High-Spin $d^6$:** (Tetrahedral is generally high spin). Splitting is reversed: $e$ is lower, $t_2$ is higher. $t_{2g}$ becomes $t_2$, $e_g$ becomes $e$. Configuration is $e^3 t_2^3$. $\text{CFSE} = [-0.6(3) + 0.4(3)]\Delta_t = [-1.8 + 1.2]\Delta_t = -0.6\Delta_t$. The values are $-0.4\Delta_o$ and $-0.6\Delta_t$.