Determine the absolute magnitude of the Crystal Field Stabilization Energy (CFSE) in terms of for a — Coordination Compounds Chemistry Question

💡 Solution & Explanation

For a high-spin $d^4$ octahedral complex, the ligands are weak, so $\Delta_o < P$. The electrons fill according to Hund's rule: $t_{2g}^3 e_g^1$. The CFSE formula is: $\text{CFSE} = (-0.4 \times n_{t2g} + 0.6 \times n_{eg}) \Delta_o$. $\text{CFSE} = (-0.4 \times 3 + 0.6 \times 1) \Delta_o = (-1.2 + 0.6) \Delta_o = -0.6 \Delta_o$. Since $1 \Delta_o = 10 Dq$, the CFSE in $Dq$ is $-0.6 \times 10 = -6 Dq$. The absolute magnitude is $6$.