The Crystal Field Stabilization Energy (CFSE) for the octahedral complex is experimentally determine — Coordination Compounds Chemistry Question
Question
The Crystal Field Stabilization Energy (CFSE) for the octahedral complex $[CoCl_6]^{4-}$ is experimentally determined to be $18000 \text{ cm}^{-1}$. Predict the CFSE for the tetrahedral complex $[CoCl_4]^{2-}$ in $\text{cm}^{-1}$, assuming all other factors remain constant.
💡 Solution & Explanation
The relationship between the crystal field splitting energy in an octahedral field ($\Delta_o$) and a tetrahedral field ($\Delta_t$) for the same metal, same oxidation state, and same ligands is given by the fundamental CFT formula: $\Delta_t = \frac{4}{9} \Delta_o$. Given $\Delta_o = 18000 \text{ cm}^{-1}$. $\Delta_t = \frac{4}{9} \times 18000 = 4 \times 2000 = 8000 \text{ cm}^{-1}$.