Coordination CompoundshardNUMERICAL

Calculate the numerical difference between the Effective Atomic Number (EAN) of Platinum in the compCoordination Compounds Chemistry Question

Question

Calculate the numerical difference between the Effective Atomic Number (EAN) of Platinum in the complex $[Pt(NH_3)_6]^{4+}$ and the EAN of Palladium in the complex $[Pd(NH_3)_6]^{4+}$. (Atomic numbers: Pt = 78, Pd = 46)

Answer: 32

💡 Solution & Explanation

Both complexes have a central metal in the $+4$ oxidation state and a coordination number of $6$. EAN of $Pt$ in $[Pt(NH_3)_6]^{4+} = 78 - 4 + 2(6) = 74 + 12 = 86$ (matches Radon). EAN of $Pd$ in $[Pd(NH_3)_6]^{4+} = 46 - 4 + 2(6) = 42 + 12 = 54$ (matches Xenon). The numerical difference is $86 - 54 = 32$.

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