Coordination CompoundshardNUMERICAL

Determine the total number of atoms present in one complete molecule of the neutral coordination comCoordination Compounds Chemistry Question

Question

Determine the total number of atoms present in one complete molecule of the neutral coordination complex 'triamminetrinitrito-N-cobalt(III)'.

Answer: 22

💡 Solution & Explanation

The IUPAC name indicates a cobalt(III) center with 3 ammine ($NH_3$) ligands and 3 nitrito-N ($NO_2^-$) ligands. The complex is neutral. The formula is $[Co(NO_2)_3(NH_3)_3]$. Breaking down the atoms: $1$ $Co$ atom + $3 \times (1 \text{ N} + 2 \text{ O}) = 9$ atoms from nitrito + $3 \times (1 \text{ N} + 3 \text{ H}) = 12$ atoms from ammine. Total atoms $= 1 + 9 + 12 = 22$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry