In an experiment analyzing the catalytic decay of an aqueous uniform mixture of , fixed aliquots are routinely pipetted and titrated thoroughly against standardized . At , the required neutralizer vol

Question

In an experiment analyzing the catalytic decay of an aqueous uniform mixture of $H_2O_2$, fixed $10	ext{ mL}$ aliquots are routinely pipetted and titrated thoroughly against standardized $KMnO_4$. At $t=0$, the required $KMnO_4$ neutralizer volume accurately equals $25.0 	ext{ mL}$. Over precisely $20 	ext{ minutes}$, the requisite titration volume strictly decays to exactly $12.5 	ext{ mL}$. Extrapolate logically the identical titration volume mathematically required (in mL) at the $40 	ext{ minute}$ boundary.

Prashant Kotian · Accepted Answer

Correct answer: 6.25. For direct decomposition, titrating with relies on the core principle that neutralizing volume corresponds seamlessly to the residual untempered . As the volume falls smoothly from 25.0 mL precisely down to 12.5 mL, representing identical 50% fraction depletion, it confirms the fixed theoretical half-life sits at exactly 20 minutes. Therefore, at cumulative elapsed timestamp (constituting 2 entire unbroken half-lives), the remaining concentration will divide in half once more: .

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