The rate constant for a zero-order reaction is . If the concentration of the reactant after is , cal — Chemical Kinetics Chemistry Question
Question
The rate constant $K$ for a zero-order reaction is $2 \times 10^{-2} \text{ mol L}^{-1} \text{ s}^{-1}$. If the concentration of the reactant after $25 \text{ seconds}$ is $0.5 \text{ M}$, calculate its concentration after $50 \text{ seconds}$ in molarity (M).
Answer: 0
💡 Solution & Explanation
For zero order, $[A]_t = [A]_0 - Kt$. At $t = 25 \text{ s}$, $0.5 = [A]_0 - (2 \times 10^{-2} \times 25) \Rightarrow [A]_0 - 0.5 = 0.5 \Rightarrow [A]_0 = 1.0 \text{ M}$. At $t = 50 \text{ s}$, $[A]_{50} = 1.0 - (2 \times 10^{-2} \times 50) = 1.0 - 1.0 = 0 \text{ M}$.
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