At , during a reaction of hydrogenation, the pressure of hydrogen gas decreases from to in . Calcula — Chemical Kinetics Chemistry Question
Question
At $27^\circ \text{C}$, during a reaction of hydrogenation, the pressure of hydrogen gas decreases from $2.0 \text{ atm}$ to $1.1 \text{ atm}$ in $75 \text{ minutes}$. Calculate the average rate of disappearance of hydrogen gas in $\text{M s}^{-1}$. Express your answer as $Y$, where Rate $= Y \times 10^{-6} \text{ M s}^{-1}$. (Use $R = 0.08 \text{ L atm K}^{-1} \text{ mol}^{-1}$)
Answer: 8.33
💡 Solution & Explanation
$\Delta P = 2.0 - 1.1 = 0.9 \text{ atm}$. $\Delta t = 75 \times 60 = 4500 \text{ s}$. Average Rate $= \frac{\Delta P}{RT \cdot \Delta t} = \frac{0.9}{0.08 \times 300 \times 4500} = \frac{0.9}{108000} = 8.33 \times 10^{-6} \text{ M s}^{-1}$.
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