For the homogeneous gaseous equilibrium , what will happen if the volume of the reaction container is suddenly halved at a constant temperature?

Question

For the homogeneous gaseous equilibrium $2A(g) + 3B(g) \rightleftharpoons 3C(g) + D(g)$, what will happen if the volume of the reaction container is suddenly halved at a constant temperature?

Prashant Kotian · Accepted Answer

Correct answer: A,B,D. Halving the volume instantly doubles the pressure and concentrations of all species. The system has 5 moles of gaseous reactants and 4 moles of gaseous products (). To relieve the increased pressure, the equilibrium shifts forward (towards fewer moles). Even after the shift, the volume reduction dominates, making final concentrations and total pressure higher than the initial state. remains constant as temperature is unchanged.

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