Chemical EquilibriumhardMCQ SINGLE

The vapour density of undecomposed is . When heated, it dissociates into , and the equilibrium vapouChemical Equilibrium Chemistry Question

Question

The vapour density of undecomposed $N_2O_4$ is $46$. When heated, it dissociates into $NO_2$, and the equilibrium vapour density decreases to $30$. What is the percentage dissociation of $N_2O_4$ at this temperature?

Answer: A

💡 Solution & Explanation

For $N_2O_4 \rightleftharpoons 2NO_2$, $n = 2$. The degree of dissociation $\alpha = \frac{D - d}{(n - 1)d}$, where $D$ is theoretical vapour density ($46$) and $d$ is observed vapour density ($30$). $\alpha = \frac{46 - 30}{(2 - 1) \times 30} = \frac{16}{30} = 0.5333$. The percentage dissociation is $0.5333 \times 100 = 53.3\%$.

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