For the synthesis of ammonia, , the equilibrium constant is at a certain temperature. Calculate the — Chemical Equilibrium Chemistry Question
Question
For the synthesis of ammonia, $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$, the equilibrium constant $K_c$ is $100$ at a certain temperature. Calculate the numerical value of $10 \times K_c'$ for the modified reaction $NH_3(g) \rightleftharpoons \frac{1}{2}N_2(g) + \frac{3}{2}H_2(g)$ at the same temperature.
Answer: 1
💡 Solution & Explanation
The original reaction has $K_c = 100$. The modified reaction is obtained by reversing the original reaction and dividing it by $2$ (or multiplying by $1/2$). Therefore, according to the properties of $K$, $K_c' = (K_c)^{-1/2} = (100)^{-1/2} = 1/\sqrt{100} = 1/10 = 0.1$. The question asks for $10 \times K_c' = 10 \times 0.1 = 1$.
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