Consider a series of reversible reactions occurring simultaneously: (), (), and (). What is the equi — Chemical Equilibrium Chemistry Question
Question
Consider a series of reversible reactions occurring simultaneously: $A \rightleftharpoons B$ ($K_1 = 2$), $B \rightleftharpoons C$ ($K_2 = 4$), and $C \rightleftharpoons D$ ($K_3 = 6$). What is the equilibrium constant for the overall reaction $A \rightleftharpoons D$?
Answer: C
💡 Solution & Explanation
When individual reactions are added together to form an overall reaction, their respective equilibrium constants are multiplied. The reaction $A \rightleftharpoons D$ is the sum of the three given reactions. Therefore, $K_{overall} = K_1 \times K_2 \times K_3 = 2 \times 4 \times 6 = 48$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes