Under which of the following specific conditions will the numerical value of be strictly equal to fo — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

The formula is $K_p = K_c(RT)^{\Delta n_g}$. This equality $K_p = K_c$ holds unconditionally if $\Delta n_g = 0$ (since $(RT)^0 = 1$), or if $RT = 1$ specifically (since $1^{\Delta n_g} = 1$ regardless of the value of $\Delta n_g$). Total pressure being 1 makes $K_p=K_x$, not $K_c$.