Consider the molecule tetracyanoethylene, . What is the total number of -bonds present in one molecu — Chemical Bonding Chemistry Question

💡 Solution & Explanation

The structure is $(N \equiv C)_2C=C(C \equiv N)_2$. The central $C=C$ double bond contains 1 $\pi$ -bond. Each of the four terminal $C \equiv N$ cyano groups is a triple bond, containing 2 $\pi$ -bonds each. Therefore, $1 + (4 \times 2) = 1 + 8 = 9$ total $\pi$ -bonds.