How many electrons are involved in the complete delocalization of the aromatic system in Naphthalene — Aromatic Hydrocarbons Chemistry Question

💡 Solution & Explanation

Naphthalene consists of two fused benzene rings. It contains 5 double bonds in its most common resonance structure. Thus, the total number of $\pi$ electrons is $5 \times 2 = 10$, satisfying Huckel's rule ($4n+2$ where $n=2$).