To definitively prove the mechanism of the bicarbonate test, Acetic acid () is reacted with isotopic — Aldehydes Ketones and Carboxylic Acids Chemistry Question
Question
To definitively prove the mechanism of the bicarbonate test, Acetic acid ($CH_3COOH$) is reacted with isotopically labelled sodium bicarbonate ($NaH^{14}CO_3$). Where will the radioactive Carbon-14 isotope strictly end up in the final products?
Answer: D
💡 Solution & Explanation
The bicarbonate test involves an acid-base reaction where the acidic proton from the carboxylic acid protonates the bicarbonate ion ($-HCO_3$) to form carbonic acid ($H_2CO_3$), which instantly decomposes into $H_2O$ and $CO_2$. Therefore, the carbon in the evolved $CO_2$ gas originates exclusively from the bicarbonate, carrying the C-14 label.
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