2-Methylpropane-1,2-diol () is subjected to oxidative cleavage using periodic acid (). What are the — Alcohols Phenols and Ethers Chemistry Question
Question
2-Methylpropane-1,2-diol ($CH_3-C(CH_3)(OH)-CH_2OH$) is subjected to oxidative cleavage using periodic acid ($HIO_4$). What are the final isolated organic products of this specific reaction?
Answer: A
💡 Solution & Explanation
Periodic acid ($HIO_4$) cleaves the $C-C$ bond of vicinal diols. The carbon with the tertiary alcohol group (bonded to two methyls) oxidizes to a ketone (propanone / acetone). The carbon with the primary alcohol group oxidizes to an aldehyde (methanal / formaldehyde).
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