Haloalkanes and HaloareneshardMCQ MULTIPLE

Intense applied heating drastically and irreversibly alters the mechanistic pathways of haloalkanes.Haloalkanes and Haloarenes Chemistry Question

Question

Intense applied heating drastically and irreversibly alters the mechanistic pathways of haloalkanes. When evaluating the fierce kinetic competition exactly between $S_N2$ and $E2$ for a specific secondary alkyl halide reacting with alcoholic $KOH$, which of the following physical truths rigorously dictate exactly why extremely high heat strongly promotes the alkene elimination product over substitution?

Answer: A,C

💡 Solution & Explanation

A) True. In a concerted $E2$ elimination, multiple strong bonds must be aggressively reorganized simultaneously (violently breaking $C-H$ and $C-X$, while meticulously making a $C=C$ pi bond), generally resulting in a measurably higher activation energy ($E_{a(elim)}$) than simply displacing a leaving group in $S_N2$ ($E_{a(sub)}$). C) True. Based entirely on the fundamental Arrhenius exponential relationship ($k = Ae^{-E_a/RT}$), a higher applied temperature disproportionately and overwhelmingly accelerates the chemical reaction structurally possessing the larger activation energy. Thus, applying intense extreme heat violently boosts the rate of the typically sluggish $E2$ pathway much more significantly than the $S_N2$ pathway, rapidly causing elimination to eventually completely overtake substitution. (Option B is chemically false. Option D is completely false; intense heating absolutely does not magically change the fundamental molecularity or the concerted nature of the mechanism if a strong base is already actively present).

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full IChO (Chemistry Olympiad) content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry