Thermodynamics and ThermochemistryhardNUMERICAL

A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constanThermodynamics and Thermochemistry Chemistry Question

Question

A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0°C. As it does so, it absorbs 208 J of heat. What is the value of work ($w$) in Joules for the process according to IUPAC sign convention?

Answer: -208

💡 Solution & Explanation

For an isothermal process involving an ideal gas, the change in internal energy ($\Delta U$) is absolutely 0. According to the First Law of Thermodynamics, $\Delta U = q + w$. Thus, $0 = 208 \text{ J} + w$, giving $w = -208$ J. The negative sign correctly indicates work is done *by* the system.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full IChO (Chemistry Olympiad) content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry