A solid cube of side acts as an adsorbent. To increase its adsorption capacity, it is finely divided — Surface Chemistry Chemistry Question

💡 Solution & Explanation

Initial volume $= 10^3 = 1000\text{ cm}^3$. Initial area $= 6 \times 10^2 = 600\text{ cm}^2$. The cube is divided into $10^{12}$ smaller cubes. Volume of each smaller cube $= 1000 / 10^{12} = 10^{-9}\text{ cm}^3$. Side of smaller cube $a = (10^{-9})^{1/3} = 10^{-3}\text{ cm}$. Area of one smaller cube $= 6 \times a^2 = 6 \times 10^{-6}\text{ cm}^2$. Total new area $= 10^{12} \times 6 \times 10^{-6} = 6 \times 10^6\text{ cm}^2$. Factor of increase $= \frac{6 \times 10^6}{600} = 10^4 = 10000$.