States of Matter and Gaseous StatehardMCQ SINGLE

At exactly the critical temperature, critical pressure, and critical volume, the theoretical criticaStates of Matter and Gaseous State Chemistry Question

Question

At exactly the critical temperature, critical pressure, and critical volume, the theoretical critical compressibility factor ($Z_c$) for any gas strictly obeying the van der Waals equation evaluates to:

Answer: B

💡 Solution & Explanation

The critical constants for a van der Waals gas are $P_c = a / 27b^2$, $V_c = 3b$, and $T_c = 8a / 27Rb$. Substituting these into the compressibility factor formula $Z_c = P_c V_c / R T_c$, we get $(a/27b^2) \times 3b / [R \times (8a/27Rb)] = (a/9b) \times (27b/8a) = 3/8 = 0.375$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full IChO (Chemistry Olympiad) content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry