If the absolute temperature of a sample of an ideal gas is raised from to , the average kinetic ener — States of Matter and Gaseous State Chemistry Question
Question
If the absolute temperature of a sample of an ideal gas is raised from $20^\circ\text{C}$ to $40^\circ\text{C}$, the average kinetic energy of its molecules changes by a precise factor of:
Answer: B
💡 Solution & Explanation
The average translational kinetic energy of an ideal gas is directly proportional to its absolute temperature in Kelvin ($KE \propto T$). $T_1 = 20 + 273 = 293\text{ K}$ and $T_2 = 40 + 273 = 313\text{ K}$. Therefore, the ratio $KE_2/KE_1 = T_2/T_1 = 313/293$.
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