At a certain temperature for which , the density of a gas, in , follows the experimental relation , — States of Matter and Gaseous State Chemistry Question
Question
At a certain temperature for which $RT = 25\text{ L atm mol}^{-1}$, the density of a gas, in $\text{g L}^{-1}$, follows the experimental relation $d = 2.00P + 0.020P^2$, where $P$ is the pressure in atmosphere. Calculate the exact molecular weight of the gas in $\text{g mol}^{-1}$.
Answer: 50
💡 Solution & Explanation
At low pressure (as $P \to 0$), real gases approach ideal behavior. For an ideal gas, $M = dRT/P$. From the given relation, $d/P = 2.00 + 0.020P$. Taking the limit as $P \to 0$, $d/P = 2.00$. Therefore, $M/RT = 2.00 \implies M = 2.00 \times 25 = 50\text{ g mol}^{-1}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes