Two separate bulbs contain ideal gases A and B. The density of gas A is twice that of gas B. The mol — States of Matter and Gaseous State Chemistry Question
Question
Two separate bulbs contain ideal gases A and B. The density of gas A is twice that of gas B. The molecular mass of gas A is half that of gas B. If the two gases are at the same temperature, the ratio of the pressure of gas A to that of gas B ($P_A/P_B$) is:
Answer: D
💡 Solution & Explanation
From the ideal gas equation, $P = dRT/M$. Since temperature $T$ is constant, the ratio of pressures is $P_A/P_B = (d_A/M_A) / (d_B/M_B) = (d_A/d_B) \times (M_B/M_A)$. Given $d_A = 2d_B$ and $M_A = 0.5M_B$, we get $P_A/P_B = (2) \times (2) = 4$.
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