The interaction energy of London dispersion forces is inversely proportional to . If the distance be — States of Matter and Gaseous State Chemistry Question
Question
The interaction energy of London dispersion forces is inversely proportional to $r^x$. If the distance between two $Ar$ atoms is halved, by what factor does the magnitude of the interaction energy increase?
Answer: D
💡 Solution & Explanation
London dispersion forces have an interaction energy proportional to $1/r^6$. If the distance $r$ is halved ($r/2$), the energy scales by a factor of $1/(1/2)^6 = 2^6 = 64$.
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