Two ions, and , have ionic radii of and respectively, in a close-packed AB crystal compound. What is — Solid State Chemistry Question
Question
Two ions, $A^+$ and $B^-$, have ionic radii of $86\text{ pm}$ and $200\text{ pm}$ respectively, in a close-packed AB crystal compound. What is the predicted coordination number of the cation $A^+$?
Answer: C
💡 Solution & Explanation
The radius ratio is calculated as $\frac{r_+}{r_-} = \frac{86}{200} = 0.43$. This value falls strictly in the range of $0.414 \le \frac{r_+}{r_-} < 0.732$, which corresponds to an octahedral geometry. Therefore, the coordination number of the cation is 6.
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