In a crystalline compound, atoms of element A form a face-centered cubic (FCC) lattice. Atoms of ele — Solid State Chemistry Question
Question
In a crystalline compound, atoms of element A form a face-centered cubic (FCC) lattice. Atoms of element B occupy all the available octahedral voids and exactly half of the available tetrahedral voids. What is the precise numerical ratio of B atoms to A atoms present in the compound?
Answer: 2
💡 Solution & Explanation
A atoms form the FCC lattice, yielding an effective number of A atoms = $4$. In FCC, there are 4 octahedral voids and 8 tetrahedral voids. B occupies all 4 OVs and half of the TVs ($8/2=4$). Total B atoms = $4 + 4 = 8$. The ratio of B atoms to A atoms is $8 : 4 = 2$.
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