An ore of iron, Wustite, is analyzed and found to have the non-stoichiometric formula . The percenta — Redox Reactions and Volumetric Analysis Chemistry Question
Question
An ore of iron, Wustite, is analyzed and found to have the non-stoichiometric formula $Fe_{0.93}O$. The percentage of total iron present in the form of $Fe(III)$ ions is $P\%$. Calculate the value of $P$ (rounded off to the nearest integer).
Answer: 15
💡 Solution & Explanation
Let the number of $Fe^{3+}$ ions be $y$. The number of $Fe^{2+}$ ions is $0.93 - y$. To balance the -2 charge of oxygen: $3y + 2(0.93 - y) = 2 \Rightarrow y + 1.86 = 2 \Rightarrow y = 0.14$. The fraction of $Fe^{3+}$ is $0.14 / 0.93 = 0.1505$. As a percentage, it is roughly $15\%$.
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