Practical Organic Chemistry and PurificationhardNUMERICAL

of an organic compound on Kjeldahlization liberates ammonia which consumes of . What is the percentaPractical Organic Chemistry and Purification Chemistry Question

Question

$1.2\ \text{g}$ of an organic compound on Kjeldahlization liberates ammonia which consumes $30\ \text{cm}^3$ of $1\ \text{N}\ HCl$. What is the percentage of nitrogen in the organic compound?

Answer: 35

💡 Solution & Explanation

Using the direct Kjeldahl formula for percentage of nitrogen: $\%N = \frac{1.4 \times N \times V}{W}$. Here, $N = 1\ \text{N}$, $V = 30\ \text{cm}^3$ (or mL), and $W = 1.2\ \text{g}$. Plugging in the values: $\%N = \frac{1.4 \times 1 \times 30}{1.2} = \frac{42}{1.2} = 35\%$.

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