Periodic Table and PeriodicityhardMCQ SINGLE

Based strictly on the differences in Pauling electronegativity values, which of the following pairs Periodic Table and Periodicity Chemistry Question

Question

Based strictly on the differences in Pauling electronegativity values, which of the following pairs correctly identifies the LEAST and MOST polar covalent bonds respectively among $C-I, N-O, C-F,$ and $P-F$?

Answer: B

💡 Solution & Explanation

Bond polarity is directly proportional to the electronegativity difference ($\Delta EN$). Approximate Pauling values: F(4.0), O(3.5), N(3.0), Cl(3.0), C(2.5), S(2.5), I(2.5), P(2.1). Differences: $C-I$ ($2.5-2.5=0$), $N-O$ ($3.5-3.0=0.5$), $C-F$ ($4.0-2.5=1.5$), $P-F$ ($4.0-2.1=1.9$). $C-I$ is the least polar (almost non-polar) and $P-F$ is the most polar.

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