Consider the elements: , and . Exactly how many of these elements have a strictly higher first ioniz — Periodic Table and Periodicity Chemistry Question
Question
Consider the elements: $Li, Be, C, N, O, F$, and $Ne$. Exactly how many of these elements have a strictly higher first ionization energy than Boron ($B$)?
Answer: 6
💡 Solution & Explanation
The trend for $IE_1$ across the second period, accounting for anomalies, is $Li < B < Be < C < O < N < F < Ne$. Boron has a lower IE than Beryllium due to $2p$ vs $2s$ penetration. Therefore, all listed elements except Lithium are higher than Boron. These are $Be, C, N, O, F, Ne$, totaling 6 elements.
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