If the single covalent radius of a carbon atom is given as , what is the estimated internuclear dist — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

The covalent radius of an element in a homonuclear single bond is half the internuclear distance. Therefore, internuclear distance $= 2 \times r_{\text{covalent}} = 2 \times 0.77 \text{ \AA} = 1.54 \text{ \AA}$. To convert to picometers ($1 \text{ \AA} = 100 \text{ pm}$), it is $1.54 \times 100 = 154 \text{ pm}$.