Periodic Table and PeriodicityhardNUMERICAL

Based on the Aufbau principle and general electronic configurations, exactly how many elements presePeriodic Table and Periodicity Chemistry Question

Question

Based on the Aufbau principle and general electronic configurations, exactly how many elements present in the $3^{rd}$ period of the modern periodic table contain electrons in the $3d$ subshell in their ground state?

Answer: 0

💡 Solution & Explanation

The 3rd period corresponds to the principal quantum number $n=3$. The sequence of subshell filling for this period involves only $3s$ and $3p$. According to the $(n+l)$ rule, the $3d$ subshell ($n+l = 3+2=5$) is of higher energy than the $4s$ subshell ($n+l = 4+0=4$) and begins filling only in the 4th period. Therefore, zero elements in the 3rd period have 3d electrons.

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