A precipitate of () is obtained when equal volumes of which of the following pairs of solutions are — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

Mixing equal volumes halves the initial concentrations. We must evaluate the ionic product $Q = [Ca^{2+}][F^-]^2$ and find where $Q > K_{sp}$. For Option B: Final $[Ca^{2+}] = 0.5 \times 10^{-2} = 5 \times 10^{-3}$, Final $[F^-] = 0.5 \times 10^{-3} = 5 \times 10^{-4}$. $Q = (5 \times 10^{-3}) \times (5 \times 10^{-4})^2 = (5 \times 10^{-3}) \times (25 \times 10^{-8}) = 125 \times 10^{-11} = 1.25 \times 10^{-9}$. Since $1.25 \times 10^{-9} > 1.7 \times 10^{-10}$, precipitation occurs.