The molar solubility of a sparingly soluble salt in water is '' . Its corresponding solubility produ — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The salt $MX_4$ dissociates as $MX_4 (s) \rightleftharpoons M^{4+} (aq) + 4X^- (aq)$. If the molar solubility is $s$, at equilibrium $[M^{4+}] = s$ and $[X^-] = 4s$. The solubility product is $K_{sp} = [M^{4+}][X^-]^4 = (s)(4s)^4 = 256s^5$. Rearranging for $s$, we get $s^5 = K_{sp} / 256$, which means $s = (K_{sp} / 256)^{1/5}$.