Calculate the exact degree of hydrolysis () for a solution of sodium acetate () at . Given and . If — Ionic Equilibrium Chemistry Question
Question
Calculate the exact degree of hydrolysis ($h$) for a $0.1 \text{ M }$ solution of sodium acetate ($CH_3COONa$) at $25^\circ C$. Given $K_a(CH_3COOH) = 1.0 \times 10^{-5}$ and $K_w = 1.0 \times 10^{-14}$. If the degree of hydrolysis is $x \times 10^{-4}$, find the exact numerical value of $x$.
Answer: 1
💡 Solution & Explanation
$CH_3COONa$ is a salt of a weak acid and strong base. The hydrolysis constant is $K_h = K_w / K_a = 10^{-14} / 10^{-5} = 10^{-9}$. The degree of hydrolysis is $h = \sqrt{K_h / C} = \sqrt{10^{-9} / 0.1} = \sqrt{10^{-8}} = 10^{-4}$. Setting this equal to $x \times 10^{-4}$ gives $x = 1$.
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