In the industrial synthesis of ammonia via Haber's process, how many moles of dihydrogen gas are req — Hydrogen Chemistry Question
Question
In the industrial synthesis of ammonia via Haber's process, how many moles of dihydrogen gas are required to completely and stoichiometrically react with exactly $5\text{ moles}$ of nitrogen gas ($N_2$)?
Answer: 15
💡 Solution & Explanation
The balanced equation for Haber's process is $N_2 + 3H_2 \rightleftharpoons 2NH_3$. For every $1\text{ mole}$ of $N_2$, $3\text{ moles}$ of $H_2$ are required. Therefore, $5\text{ moles}$ of $N_2$ will require $5 \times 3 = 15\text{ moles}$ of $H_2$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes